mean).## S3 method for class 'RasterLayer':
aggregate(x, fact=2, fun=mean, expand=TRUE, na.rm=TRUE, filename='', ...)
## S3 method for class 'RasterStackBrick':
aggregate(x, fact=2, fun=mean, expand=TRUE, na.rm=TRUE, filename='', ...)
## S3 method for class 'SpatialPolygons':
aggregate(x, v, ...)TRUE the output RasterLayer will be larger then the input RasterLayer if a division
of the number of columns or rows with factor is not an integerTRUE, NA cells are removed from calculationswriteRasterfact*fact fewer cells; if necessary this number is adjusted according to the value of expand.
For example, fact=2 will result in a new Raster* object with 2*2=4 times fewer cells. If two numbers are supplied, e.g., fact=c(2,3), the first will be used for aggregating in the horizontal direction,
and the second for aggregating in the vertical direction, and the new RasterLayer will have 2*3=6 times fewer cells.
Aggregation starts at the upper-left end of a raster. If a division of the number of columns or rows with factor does not
return an integer, the extent of the resulting Raster object will either be somewhat smaller or somewhat larger then the original RasterLayer.
For example, if an input RasterLayer has 100 columns, and fact=12, the output Raster object will have either 8 columns (expand=FALSE)
(using 8 x 12 = 96 of the original columns) or 9 columns (expand=TRUE). In both cases, the maximum x coordinate of the output RasterLayer would, of course, also be adjusted.
The function fun should take multiple numbers, and return a single number. For example mean, modal, min or max.
It should also accept a na.rm argument (or ignore it as one of the 'dots' arguments).disaggregate, resampler <- raster()
# a new aggregated raster, no values
ra <- aggregate(r, fact=10)
r <- setValues(r, runif(ncell(r)))
ra <- aggregate(r, fact=10, fun=max)
# a new aggregated raster, max of the valuesRun the code above in your browser using DataLab