parst3
. There is no explicit solution for the cumulative distribution function for value X
but built-in Rfunctions can be used. For $\nu \ge 1000$, pnorm(X, mean=U, sd=A)
for U
= $\xi$ and A
= $\alpha$ for $1.000001 \le \nu \le 1000$, pt((X-U)/A, N)
for N
= $\nu$ and where pnorm()
is for the Normal distribution and pt()
is the 1-parameter Student T distribution.cdfst3(x, para, paracheck=TRUE)
parst3
or similar.quast3
, parst3
, pdfst3
lmr <- lmoms(c(123,34,4,654,37,78))
cdfst3(191.5143, parst3(lmr)) # 75th percentile
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