
Given a solution of a model and observed data, estimates the residuals, and the variable and model costs (sum of squared residuals).
modCost(model, obs, x = "time", y = NULL, err = NULL,
weight = "none", scaleVar = FALSE, cost = NULL, ...)
a list of type modCost
containing:
one value, the model cost, which equals the sum of scaled variable costs (see details).
one value, -log(model probablity), where it is assumed
that the data are normally distributed, with standard deviation =
error
.
the variable costs, a data.frame with, for each observed variable the following (see details):
name, the name of the observed variable.
scale, the scale-factor used to weigh the variable cost, either 1 or 1/(number observations), defaults to 1.
N, the number of data points per observed variable.
SSR.unweighted, the sum of squared residuals per observed variable, unweighted.
SSR, the sum of weighted squared residuals per observed variable(see details).
the data residual, a data.frame with several columns:
name, the name of the observed variable.
x, the value of the independent variable (if present).
obs, the observed variable value.
mod, the corresponding modeled value.
weight, the factor used to weigh the residuals, 1/error, defaults to 1.
res, the weighted residuals between model and observations (mod-obs)*weight.
res.unweighted, the residuals between model and observations (mod-obs).
model output, as generated by the integration routine or the steady-state solver, a matrix or a data.frame, with one column per dependent and independent variable.
the observed data, either in long (database) format (name, x, y), a data.frame, or in wide (crosstable, or matrix) format - see details.
the name of the independent variable; it should be a
name occurring both in the obs
and model
data
structures.
either NULL
, the name of the column with the
dependent variable values,or an index to the dependent
variable values; if NULL
then the observations are assumed to
be in crosstable (matrix) format, and the names of the independent
variables are given by the column names of this matrix.
either NULL
, or the name of the column with the
error estimates, used to weigh the residuals (see details);
if NULL
, then the residuals are not weighed.
if not NULL
, the output of a previous call to
modCost
; in this case, the new output will combine both.
only if err
=NULL
: how to weigh the
residuals, one of "none", "std", "mean", see details.
if TRUE
, then the residuals of one observed
variable are scaled respectively to the number of observations (see
details).
additional arguments passed to R-function approx
.
Karline Soetaert <karline.soetaert@nioz.nl>
This function compares model output with observed data.
It computes
the weighted residuals, one for each data point.
the variable costs, i.e. the sum of squared weight residuals per variable.
the model cost, the scaled sum of variable costs .
There are three steps:
1. For any observed data point, i, the weighted
residuals are estimated as:
The weights are equal to 1/error, where the latter can be inputted,
one for each data point by specifying err
as an extra column in
the observed data.
This can only be done when the data input is in long (database) format.
When err
is not inputted, then the weights are specified via argument
weight
which is either:
"none"
, which sets the weight equal to 1 (the default)
"std"
, which sets the weights equal to the reciprocal of the standard deviation
of the observed data (can only be used if there is more than 1 data point)
"mean"
, which uses 1/mean of the absolute value of the
observed data (can only be used if not 0).
2. Then for each observed variable, j, a variable cost is estimated as the sum of squared weighted residuals for this variable:
where
3. Finally, the model Cost is estimated as the scaled sum of variable costs:
and where scaleVar
. If TRUE
, then the variable
costs are rescaled. The default is NOT to rescale
(i.e.
The models typically consist of (a system of) differential equations, which are either solved by:
integration routines, e.g. the routines from package deSolve
,
steady-state estimators, as from package rootSolve
.
The data can be presented in two formats:
data table (long) format; this is a two to four column
data.frame that contains the name
of the observed variable (always
the FIRST column), the (optional) value of the independent variable
(default column name = "time"), the value of the observation
and
the (optional) value of the error
.
For data presented in this format, the names of the column(s) with the
independent variable (x
) and the name of the column that has the
value of the dependent variable y
must be passed to function
modCost
.
crosstable (wide) format; this is a matrix, where each
column denotes one dependent (or independent) variable; the column name
is the name of the observed variable.
When using this format, only the name of the column that contains the
dependent variable must be specified (x
).
As an example of both formats consider the data, called Dat
consisting
of two observed variables, called "Obs1" and "Obs2", both containing two
observations, at time 1 and 2:
name | time | val | err |
Obs1 | 1 | 50 | 5 |
Obs1 | 2 | 150 | 15 |
Obs2 | 1 | 1 | 0.1 |
Obs2 | 2 | 2 | 0.2 |
for the long format and
time | Obs1 | Obs2 |
1 | 50 | 1 |
2 | 150 | 2 |
for the crosstab format. Note, that in the latter case it is not possible to provide separate errors per data point.
By calling modCost several consecutive times (using the cost
argument),
it is possible to combine both types of data files.
Soetaert, K. and Petzoldt, T. 2010. Inverse Modelling, Sensitivity and Monte Carlo Analysis in R Using Package FME. Journal of Statistical Software 33(3) 1--28. tools:::Rd_expr_doi("10.18637/jss.v033.i03")
## =======================================================================
## Type 1 input: name, time, value
## =======================================================================
## Create new data: two observed variables, "a", "b"
Data <- data.frame(name = c(rep("a", 4), rep("b", 4)),
time = c(1:4, 2:5), val = c(runif(4), 1:4))
## "a nonsense model"
Mod <- function (t, y, par) {
da <- 0
db <- 1
return(list(c(da, db)))
}
out <- ode(y = c(a = 0.5, b = 0.5), times = 0:6, func = Mod, parms = NULL)
Data # Show
out
## The cost function
modCost(model = out, obs = Data, y = "val")
## The cost function with a data error added
Dat2 <- cbind(Data, Err = Data$val*0.1) # error = 10% of value
modCost(model = out, obs = Dat2, y = "val", err = "Err")
## =======================================================================
## Type 2 input: Matrix format; column names = variable names
## =======================================================================
## logistic growth model
TT <- seq(1, 100, 2.5)
N0 <- 0.1
r <- 0.5
K <- 100
## analytical solution
Ana <- cbind(time = TT, N = K/(1 + (K/N0 - 1) * exp(-r*TT)))
## numeric solution
logist <- function(t, x, parms) {
with(as.list(parms), {
dx <- r * x[1] * (1 - x[1]/K)
list(dx)
})
}
time <- 0:100
parms <- c(r = r, K = K)
x <- c(N = N0)
## Compare several numerical solutions
Euler <- ode(x, time, logist, parms, hini = 2, method = "euler")
Rk4 <- ode(x, time, logist, parms, hini = 2, method = "rk4")
Lsoda <- ode(x, time, logist, parms) # lsoda is default method
Ana2 <- cbind(time = time, N = K/(1 + (K/N0 - 1) * exp(-r * time)))
## the SSR and residuals with respect to the "data"
cEuler <- modCost(Euler, Ana)$model
cRk4 <- modCost(Rk4 , Ana)$model
cLsoda <- modCost(Lsoda, Ana)$model
cAna <- modCost(Ana2 , Ana)$model
compare <- data.frame(method = c("euler", "rk4", "lsoda", "Ana"),
cost = c(cEuler, cRk4, cLsoda, cAna))
## Plot Euler, RK and analytic solution
plot(Euler, Rk4, col = c("red", "blue"), obs = Ana,
main = "logistic growth", xlab = "time", ylab = "N")
legend("bottomright", c("exact", "euler", "rk4"), pch = c(1, NA, NA),
col = c("black", "red", "blue"), lty = c(NA, 1, 2))
legend("right", ncol = 2, title = "SSR",
legend = c(as.character(compare[,1]),
format(compare[,2], digits = 2)))
compare
## =======================================================================
## Now suppose we do not know K and r and they are to be fitted...
## The "observations" are the analytical solution
## =======================================================================
## Run the model with initial guess: K = 10, r = 2
parms["K"] <- 10
parms["r"] <- 2
init <- ode(x, time, logist, parms)
## FITTING algorithm uses modFit
## First define the objective function (model cost) to be minimised
## more general: using modFit
Cost <- function(P) {
parms["K"] <- P[1]
parms["r"] <- P[2]
out <- ode(x, time, logist, parms)
return(modCost(out, Ana))
}
(Fit<-modFit(p = c(K = 10, r = 2), f = Cost))
summary(Fit)
## run model with the optimized value:
parms[c("K", "r")] <- Fit$par
fitted <- ode(x, time, logist, parms)
## show results, compared with "observations"
plot(init, fitted, col = c("green", "blue"), lwd = 2, lty = 1,
obs = Ana, obspar = list(col = "red", pch = 16, cex = 2),
main = "logistic growth", xlab = "time", ylab = "N")
legend("right", c("initial", "fitted"), col = c("green", "blue"), lwd = 2)
Cost(Fit$par)
Run the code above in your browser using DataLab