GENLIB (version 1.1.10)

gen.simuProb: Gene dropping simulations - Probabilities

Description

Returns the probabilities that specified probands inherit disease alleles from ancestors.

Usage

gen.simuProb(gen, pro, statePro, ancestors, stateAncestors, simulNo=5000, 
                    probRecomb=c(0,0), probSurvival=1.0)

Value

A list containing the following:

the joint probability of specified statePro for all probands,

the probability of specified statePro for each proband,

the probability that, 0, 1, ..., and all probands inherit the specified number of disease alleles.

Arguments

gen

An object of class GLgen obtained with gen.genealogy, gen.lineages or gen.branching. Required.

pro

Vector of proband id numbers to be included. Required.

statePro

Required vector indicating, for each proband in pro, the probability to be calculated:

0 = no disease allele is transmitted

1 = 1 disease allele is transmitted

2 = 2 disease alleles are transmitted

3 = 1 or 2 disease alleles are transmitted

ancestors

Vector of ancestors id numbers to be included. Required.

stateAncestors

Required vector indicating, for each ancestor in ancestors, the genotype state:

0 = no disease allele present

1 = 1 disease allele present

2 = 2 disease alleles present

simulNo

Number of simulations to perform. Default is 5000.

probRecomb

Recombination probabilities for males and females. Default is no recombination.

probSurvival

Survival probability for homozygotes. Default is 1.

See Also

gen.genealogy gen.simuSample gen.simuSet gen.simuSampleFreq

Examples

data(geneaJi) 
genJi<-gen.genealogy(geneaJi) 
# Probability that subjects 1 and 29 get 1 and 2 alleles from ancestors 20 and 25,
# that have themselves 2 and 1.
gen.simuProb(genJi, pro=c(1,29), statePro=c(1,2), ancestors=c(20,25), stateAncestors=c(2,1),
             simulNo=10000)
# Probability that subjects 1 and 29 get 1 segment from ancestors 25,
# knowing the segment has a male
# recombination rate of 0.02 and a female recombination rate of 0.04.
gen.simuProb(genJi, pro=c(1,29), statePro=c(1,1), ancestors=c(25), stateAncestors=c(1),
             simulNo=10000, probRecomb = c(0.02, 0.04))
# Probability that subjects 1 and 29 get 1 and 2 alleles from ancestors 20 and 25,
# that have themselves 2 and 1 and knowing that homozygous people have a survival rate
# of 0.50.
gen.simuProb(genJi, pro=c(1,29), statePro=c(1,2), ancestors=c(20,25), stateAncestors=c(2,1),
             simulNo=10000, probSurvival=0.5)