Logical argument for the option of normalizing value of TE (transfer entropy) (FALSE by default).
This normalization is different from the discrete case, because, here the term H (X(t)| X(t-1), ..., X(t-p)) may be negative.
Consequently, we use another technique, we divide TE by H0 - H (X(t)| X(t-1), ..., X(t-p), Yt-1), ..., Y(t-q)), where H0 is the max entropy (of uniform distribution).