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PerMallows (version 1.8)

count.perms.unfixed.points.gtet: Count permutations with at least a given number of unfixed points

Description

Given the number of items in the permutations and the number of unfixed points u, how many permutations are there with at least u unfixed points?

Usage

count.perms.unfixed.points.gtet(perm.length, unfixed = perm.length)

Arguments

perm.length
number of items in the permutations
unfixed
optional the number of unfixed points

Value

  • The number of permutations in which the number of unfixed points is greater than or equal to the specified argument

Examples

Run this code
count.perms.unfixed.points.gtet(4,1)

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