powered by
'months'
'years'
To support additional time units 'months' and 'years' for difftime object.
timeUnits()
Function timeUnits returns a named constant character
vector.
Every 4 years has 1461(=365*4+1) days, or 48(=4*12) months. Therefore, every month has 30.44(=1461/48) days, or 4.35(=1461/48/7) weeks.
1461(=365*4+1)
48(=4*12)
30.44(=1461/48)
4.35(=1461/48/7)
Every year has 12 months.