rep
Replicate Elements of Vectors and Lists
rep
replicates the values in x
. It is a generic
function, and the (internal) default method is described here.
rep.int
and rep_len
are faster simplified versions for
two common cases. They are not generic.
Usage
rep(x, ...)
rep.int(x, times)
rep_len(x, length.out)
Arguments
 x
 a vector (of any mode including a list) or a factor or (for
rep
only) aPOSIXct
orPOSIXlt
orDate
object; or an S4 object containing such an object.  ...
 further arguments to be passed to or from other methods.
For the internal default method these can include:
times
 A integer vector giving the (nonnegative) number of
times to repeat each element if of length
length(x)
, or to repeat the whole vector if of length 1. Negative orNA
values are an error. length.out
 nonnegative integer. The desired length of the
output vector. Other inputs will be coerced to an integer
vector and the first element taken. Ignored if
NA
or invalid. each
 nonnegative integer. Each element of
x
is repeatedeach
times. Other inputs will be coerced to an integer vector and the first element taken. Treated as1
ifNA
or invalid.
 times
 see
...
.  length.out
 nonnegative integer: the desired length of the output vector.
Details
The default behaviour is as if the call was
rep(x, times = 1, length.out = NA, each = 1). Normally just one of the additional arguments is specified, but if
each
is specified with either
of the other two, its replication is performed first, and then that
implied by times
or length.out
. If times
consists of a single integer, the result consists of
the whole input repeated this many times. If times
is a
vector of the same length as x
(after replication by
each
), the result consists of x[1]
repeated
times[1]
times, x[2]
repeated times[2]
times and
so on.
length.out
may be given in place of times
,
in which case x
is repeated as many times as is
necessary to create a vector of this length. If both are given,
length.out
takes priority and times
is ignored.
Noninteger values of times
will be truncated towards zero.
If times
is a computed quantity it is prudent to add a small
fuzz or use round
. And analogously for each
.
If x
has length zero and length.out
is supplied and is
positive, the values are filled in using the extraction rules, that is
by an NA
of the appropriate class for an atomic vector
(0
for raw vectors) and NULL
for a list.
Value

An object of the same type as
x
.rep.int
and rep_len
return no attributes (except the
class if returning a factor).The default method of rep
gives the result names (which will
almost always contain duplicates) if x
had names, but retains
no other attributes.
Note
Function rep.int
is a simple case which was provided as a
separate function partly for S compatibility and partly for speed
(especially when names can be dropped). The performance of rep
has been improved since, but rep.int
is still at least twice as
fast when x
has names.
The name rep.int
long precedes making rep
generic.
Function rep
is a primitive, but (partial) matching of argument
names is performed as for normal functions.
For historical reasons rep
(only) works on NULL
: the
result is always NULL
even when length.out
is positive.
Although it has never been documented, these functions have always worked on expression vectors.
References
Becker, R. A., Chambers, J. M. and Wilks, A. R. (1988) The New S Language. Wadsworth & Brooks/Cole.
See Also
Examples
library(base)
rep(1:4, 2)
rep(1:4, each = 2) # not the same.
rep(1:4, c(2,2,2,2)) # same as second.
rep(1:4, c(2,1,2,1))
rep(1:4, each = 2, len = 4) # first 4 only.
rep(1:4, each = 2, len = 10) # 8 integers plus two recycled 1's.
rep(1:4, each = 2, times = 3) # length 24, 3 complete replications
rep(1, 40*(1.8)) # length 7 on most platforms
rep(1, 40*(1.8)+1e7) # better
## replicate a list
fred < list(happy = 1:10, name = "squash")
rep(fred, 5)
# datetime objects
x < .leap.seconds[1:3]
rep(x, 2)
rep(as.POSIXlt(x), rep(2, 3))
## named factor
x < factor(LETTERS[1:4]); names(x) < letters[1:4]
x
rep(x, 2)
rep(x, each = 2)
rep.int(x, 2) # no names
rep_len(x, 10)
Community examples
**Reoccuring times series with fixed length** I wanted to count the days in a times series and address a yeardaynumber to each existing date in the dataset. ``` day_seq < rep(1:365, times = 3, length.out = 901) ``` This way it repeats the numbers 1 to 365, 3 times until 901 entries are made(length of my dataset).