cut.dates

0th

Percentile

Create a Factor from a Chron or Dates Object

Divide the range of a chron or dates object x into intervals and code the values in x according to which interval they fall.

Keywords
chron
Usage
## S3 method for class 'dates':
cut(x, breaks, labels, start.on.monday = TRUE, \dots)
Arguments
x
chron or dates object (see chron), character dates such as "10/04/91" or Julian dates).
breaks
either a vector of break points (a dates vector, character dates such as "10/04/91" or Julian dates), a constant specifying number of equally spaced intervals extending from min(x)-1 to max(x)+1
labels
character labels for intervals.
start.on.monday
should weeks be assumed to start on Mondays? Default is TRUE. Set to FALSE if weeks start on Sundays; for other days of the week specify the corresponding number: Sunday == 0, Monday == 1, Tuesday == 2, ..., Saturda
...
further arguments to be passed to or from methods.
Value

  • an ordered factor whose levels represent the various time intervals.

See Also

seq.dates

Aliases
  • cut.dates
Examples
# days from 07/01/92 thru 07/15/92 fell into 3 Monday-started weeks
cut(dates("07/01/92") + 0:14, "weeks")
# [1] week 1 week 1 week 1 week 1 week 1 week 2 week 2 week 2 
# [9] week 2 week 2 week 2 week 2 week 3 week 3 week 3

dts <- dates(c("02/27/92", "02/27/92", "01/14/92",
               "02/28/92", "02/01/92"))
cut(dts, "months")
# [1] Feb 92 Feb 92 Jan 92 Feb 92 Feb 92
boxplot(runif(5) ~ cut(dts, "months"))
Documentation reproduced from package chron, version 2.3-37, License: GPL-2

Community examples

Looks like there are no examples yet.