Calculate the difference from lag periods prior for log of data.
Usage
diffLog(x, lag=1, base = exp(1), ...)
Arguments
x
A time series.
lag
The difference is calculated relative to lag periods prior.
base
Base to use when calculating logrithms.
...
(further arguments, currently disregarded).
Value
A time series of the difference relative to lag periods prior for the log of
the data. lag data points are lost from the beginning of the series. Negative
values will result in NAs.