mKrig(x, y, weights = rep(1, nrow(x)), Z=NULL,
lambda = 0, cov.function = "stationary.cov",
m = 2, chol.args=NULL,cov.args=NULL, find.trA = TRUE, NtrA = 20,
iseed = 123, llambda=NULL, ...)## S3 method for class 'mKrig':
predict( object, xnew=NULL,ynew=NULL, derivative=0, Z=NULL, drop.Z=FALSE,just.fixed=FALSE, ...)
## S3 method for class 'mKrig':
summary(object, ...)
## S3 method for class 'mKrig':
print( x, digits=4,... )
mKrig.coef(object, y)
mKrig.trace( object, iseed, NtrA)
d
coefficients vector. This is helpful to distguish between polynomial part and the extra covariates coefficients associated with Z.np
then the individual members of the Monte Carlo sample and
sd(trA.info)/ sqrt(NtrA)
is an estimate of the standard error. If NtrA is greater than or equal to np
then these are the diagonal elements of A(lamdba).y
as a matrix and the computations are done efficiently for each set.
Note that this is not a multivariate spatial model just an efficient computation over
several data vectors without explicit looping. predict.mKrig
will evaluate the derivatives of the estimated
function if derivatives are supported in the covariance function.
For example the wendland.cov function supports derivatives.
print.mKrig
is a simple summary function for the object.
mKrig.coef
finds the "d" and "c" coefficients represent the
solution using the previous cholesky decomposition for a new data
vector. This is used in computing the prediction standard error in
predict.se.mKrig and can also be used to evalute the estimate
efficiently at new vectors of observations provided the locations and
covariance remain fixed.
Sparse matrix methods are handled through overloading the
usual linear algebra functions with sparse versions. But to take
advantage of some additional options in the sparse methods the list
argument chol.args is a device for changing some default values. The
most important of these is nnzR
, the number of nonzero elements
anticipated in the Cholesky factorization of the postive definite linear
system used to solve for the basis coefficients. The sparse of this
system is essentially the same as the covariance matrix evalauted at the
observed locations.
As an example of resetting nzR
to 450000 one would use the following
argument for chol.args in mKrig:
chol.args=list(pivot=TRUE,memory=list(nnzR= 450000))
mKrig.trace
This is an internal function called by mKrig
to estimate the effective degrees of freedom. The Kriging surface estimate
at the data locations is
a linear function of the data and can be represented as A(lambda)y.
The trace of A is one useful
measure of the effective degrees of freedom used in the surface
representation. In particular this figures into the GCV estimate of the smoothing parameter.
It is computationally intensive to find the trace
explicitly but there is a simple Monte Carlo estimate that is often
very useful. If E is a vector of iid N(0,1) random variables then the
trace of A is the expected value of t(E)AE. Note that AE is simply
predicting a surface at the data location using the synthetic
observation vector E. This is done for NtrA
independent N(0,1)
vectors and the mean and standard deviation are reported in the
mKrig
summary. Typically as the number of observations is
increased this estimate becomse more accurate. If NtrA is as large as
the number of observations (np
) then the algorithm switches to
finding the trace exactly based on applying A to np
unit
vectors.
mKrig.grid
#
# Midwest ozone data 'day 16' stripped of missings
data( ozone2)
y<- ozone2$y[16,]
good<- !is.na( y)
y<-y[good]
x<- ozone2$lon.lat[good,]
# nearly interpolate using defaults (Exponential)
mKrig( x,y, theta = 2.0, lambda=.01)-> out
#
# NOTE this should be identical to
# Krig( x,y, theta=2.0, lambda=.01)
# interpolate using tapered version of the exponential,
# the taper scale is set to 1.5 default taper covariance is the Wendland.
# Tapering will done at a scale of 1.5 relative to the scaling
# done through the theta passed to the covariance function.
mKrig( x,y,cov.function="stationary.taper.cov",
theta = 2.0, lambda=.01,
Taper="Wendland", Taper.args=list(theta = 1.5, k=2, dimension=2)
) -> out2
predict.surface( out2)-> out.p
surface( out.p)
# Try out GCV on a grid of lambda's.
# For this small data set
# one should really just use Krig or Tps but this is an example of
# approximate GCV that will work for much larger data sets using sparse
# covariances and the Monte Carlo trace estimate
#
# a grid of lambdas:
lgrid<- 10**seq(-1,1,,15)
GCV<- matrix( NA, 15,20)
trA<- matrix( NA, 15,20)
GCV.est<- rep( NA, 15)
eff.df<- rep( NA, 15)
logPL<- rep( NA, 15)
# loop over lambda's
for ( k in 1:15){
out<- mKrig( x,y,cov.function="stationary.taper.cov",
theta = 2.0, lambda=lgrid[k],
Taper="Wendland", Taper.args=list(theta = 1.5, k=2, dimension=2) )
GCV[k,]<- out$GCV.info
trA[k,]<- out$trA.info
eff.df[k]<- out$eff.df
GCV.est[k]<- out$GCV
logPL[k]<- out$lnProfileLike
}
#
# plot the results different curves are for individual estimates
# the two lines are whether one averages first the traces or the GCV criterion.
#
par( mar=c(5,4,4,6))
matplot( trA, GCV, type="l", col=1, lty=2, xlab="effective degrees of freedom", ylab="GCV")
lines( eff.df, GCV.est, lwd=2, col=2)
lines( eff.df, rowMeans(GCV), lwd=2)
# add exact GCV computed by Krig
out0<- Krig( x,y,cov.function="stationary.taper.cov",
theta = 2.0,
Taper="Wendland", Taper.args=list(theta = 1.5, k=2, dimension=2), spam.format=FALSE)
lines( out0$gcv.grid[,2:3], lwd=4, col="darkgreen")
# add profile likelihood
utemp<- par()$usr
utemp[3:4] <- range( -logPL)
par( usr=utemp)
lines( eff.df, -logPL, lwd=2, col="blue", lty=2)
axis( 4)
mtext( side=4,line=3, "-ln profile likelihood", col="blue")
title( "GCV ( green = exact) and -ln profile likelihood", cex=2)
# an example using a "Z" covariate and the Matern family
data(COmonthlyMet)
y<- CO.tmin.MAM.climate
good<- !is.na( y)
y<-y[good]
x<- CO.loc[good,]
Z<- CO.elev[good]
out<- mKrig( x,y, Z=Z, cov.function="stationary.cov", Covariance="Matern",
theta=4.0, smoothness=1.0, lambda=.1)
set.panel(2,1)
# quilt.plot with elevations
quilt.plot( x, predict(out))
# quilt.plot without elevation linear term included
quilt.plot( x, predict(out, drop.Z=TRUE))
set.panel()
# here is a series of examples with a bigger problem
# using a compactly supported covariance directly
set.seed( 334)
N<- 1000
x<- matrix( 2*(runif(2*N)-.5),ncol=2)
y<- sin( 1.8*pi*x[,1])*sin( 2.5*pi*x[,2]) + rnorm( 1000)*.1
look2<-mKrig( x,y, cov.function="wendland.cov",k=2, theta=.2,
lambda=.1)
# take a look at fitted surface
predict.surface(look2)-> out.p
surface( out.p)
# this works because the number of nonzero elements within distance theta
# are less than the default maximum allocated size of the
# sparse covariance matrix.
# see spam.options() for the default values
# The following will give a warning for theta=.9 because
# allocation for the covariance matirx storage is too small.
# Here theta controls the support of the covariance and so
# indirectly the number of nonzero elements in the sparse matrix
mKrig( x,y, cov.function="wendland.cov",k=2, theta=.9, lambda=.1)-> look2
# The warning resets the memory allocation for the covariance matirx according the
# values 'spam.options(nearestdistnnz=c(416052,400))'
# this is inefficient becuase the preliminary pass failed.
# the following call completes the computation in "one pass"
# without a warning and without having to reallocate more memory.
spam.options(nearestdistnnz=c(416052,400))
mKrig( x,y, cov.function="wendland.cov",k=2, theta=.9, lambda=1e-2)-> look2
# as a check notice that
# print( look2)
# report the number of nonzero elements consistent with the specifc allocation
# increase in spam.options
# new data set of 1500 locations
set.seed( 234)
N<- 1500
x<- matrix( 2*(runif(2*N)-.5),ncol=2)
y<- sin( 1.8*pi*x[,1])*sin( 2.5*pi*x[,2]) + rnorm( N)*.01
# the following is an example of where the allocation (for nnzR)
# for the cholesky factor is too small. A warning is issued and
# the allocation is increased by 25% in this example
#
mKrig( x,y,
cov.function="wendland.cov",k=2, theta=.1,
lambda=1e2 )-> look2
# to avoid the warning
mKrig( x,y,
cov.function="wendland.cov",k=2, theta=.1,
lambda=1e2,
chol.args=list(pivot=TRUE,memory=list(nnzR= 450000)) )-> look2
# success!
# fiting multiple data sets
#
#\dontrun{
y1<- sin( 1.8*pi*x[,1])*sin( 2.5*pi*x[,2]) + rnorm( N)*.01
y2<- sin( 1.8*pi*x[,1])*sin( 2.5*pi*x[,2]) + rnorm( N)*.01
Y<- cbind(y1,y2)
mKrig( x,Y,cov.function="wendland.cov",k=2, theta=.1,
lambda=1e2 )-> look3
# note slight difference in summary because two data sets have been fit.
print( look3)
#}
##################################################
# finding a good choice for theta as a taper
##################################################
# Suppose the target is a spatial prediction using roughly 50 nearest neighbors
# (tapering covariances is effective for roughly 20 or more in the situation of
# interpolation) see Furrer, Genton and Nychka (2006).
# take a look at a random set of 100 points to get idea of scale
set.seed(223)
ind<- sample( 1:N,100)
hold<- rdist( x[ind,], x)
dd<- (apply( hold, 1, sort))[65,]
dguess<- max(dd)
# dguess is now a reasonable guess at finding cutoff distance for
# 50 or so neighbors
# full distance matrix excluding distances greater than dguess
# but omit the diagonal elements -- we know these are zero!
hold<- nearest.dist( x, delta= dguess,upper=TRUE)
# exploit spam format to get quick of number of nonzero elements in each row
hold2<- diff( hold@rowpointers)
# min( hold2) = 55 which we declare close enough
# now the following will use no less than 55 nearest neighbors
# due to the tapering.
mKrig( x,y, cov.function="wendland.cov",k=2, theta=dguess,
lambda=1e2) -> look2
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