data('votB')
ex1 <- lba(city ~ parties,
data=votB,
K = 2)
plot(ex1)
# It's very simple. with colors!
plot(ex1,
col.points=1:6,
col.lines=1:6)
# I don't want your output. I want to provide my values and to use only your graphics. Ok!!!!
# Example: pag. 34, inner extreme solution
k1 <- c(.16,.68,.06,.45,.54,.30,.00,.45,1 ,.19,.62,.68,.57,.50,.30,
.88,.46,.09,.62,.26,.53,.47,.58,.09,.26,.40,.70,.16,.71,.32)
k2 <- c(.84,.32,.94,.55,.46,.7 , 1,.55,.00,.81,.38,.32,.43,.50,.7,
.12,.54,.91,.38,.74,.47,.53,.42,.91,.74,.60,.30,.84,.29,.68)
my_mixing <- cbind(k1,k2)
rownames(my_mixing) <- paste(rep(c('H','C','R','Q','T','N','Se','Sk','L','V'),
rep(3,10)),
c('+','=','-'),
sep = '')
my_budget <- matrix(c(.43,.57),
ncol=2)
colnames(my_budget) <- paste('LB',1:2,sep='')
my_data <- list(NA,
NA,
NA,
NA,
NA,
my_mixing,
NA,
NA,
my_budget)
class(my_data) = 'lba'
# I didn't like. I want equal of book. Pag. 41.
l_points <- c(2,24,17,
rep(3,3),
6,6,25,
rep(4,3),
1,16,21,
rep(11,3),
5,5,23,
rep(8,3),
rep(9,3),
rep(13,3))
my_colors <- rep(c('red','blue','black'),
10)
plot(my_data,
pch.points = l_points,
col.points = my_colors,
lty.budget = 2,
pch.budget = 7,
legend = FALSE)
legend(-0.1,
1.2,
rownames(my_mixing),
pch = l_points,
col = my_colors,
xpd = TRUE,
cex = 0.8,
ncol = 10) # Is beautiful!!Run the code above in your browser using DataLab