```
# Solve the following system: Ax=B, where A is block diagonal, and
# 0.0 -0.98 -0.79 -0.15 Top
# -1.00 0.25 -0.87 0.35 Top
# 0.78 0.31 -0.85 0.89 -0.69 -0.98 -0.76 -0.82 blk1
# 0.12 -0.01 0.75 0.32 -1.00 -0.53 -0.83 -0.98
# -0.58 0.04 0.87 0.38 -1.00 -0.21 -0.93 -0.84
# -0.21 -0.91 -0.09 -0.62 -1.99 -1.12 -1.21 0.07
# 0.78 -0.93 -0.76 0.48 -0.87 -0.14 -1.00 -0.59 blk2
# -0.99 0.21 -0.73 -0.48 -0.93 -0.91 0.10 -0.89
# -0.68 -0.09 -0.58 -0.21 0.85 -0.39 0.79 -0.71
# 0.39 -0.99 -0.12 -0.75 -0.68 -0.99 0.50 -0.88
# 0.71 -0.64 0.0 0.48 Bot
# 0.08 100.0 50.00 15.00 Bot
B <- c(-1.92, -1.27, -2.12, -2.16, -2.27, -6.08,
-3.03, -4.62, -1.02, -3.52, 0.55, 165.08)
AA <- matrix (nrow = 12, ncol = 12, 0)
AA[1,1:4] <- c( 0.0, -0.98, -0.79, -0.15)
AA[2,1:4] <- c(-1.00, 0.25, -0.87, 0.35)
AA[3,1:8] <- c( 0.78, 0.31, -0.85, 0.89, -0.69, -0.98, -0.76, -0.82)
AA[4,1:8] <- c( 0.12, -0.01, 0.75, 0.32, -1.00, -0.53, -0.83, -0.98)
AA[5,1:8] <- c(-0.58, 0.04, 0.87, 0.38, -1.00, -0.21, -0.93, -0.84)
AA[6,1:8] <- c(-0.21, -0.91, -0.09, -0.62, -1.99, -1.12, -1.21, 0.07)
AA[7,5:12] <- c( 0.78, -0.93, -0.76, 0.48, -0.87, -0.14, -1.00, -0.59)
AA[8,5:12] <- c(-0.99, 0.21, -0.73, -0.48, -0.93, -0.91, 0.10, -0.89)
AA[9,5:12] <- c(-0.68, -0.09, -0.58, -0.21, 0.85, -0.39, 0.79, -0.71)
AA[10,5:12]<- c( 0.39, -0.99, -0.12, -0.75, -0.68, -0.99, 0.50, -0.88)
AA[11,9:12]<- c( 0.71, -0.64, 0.0, 0.48)
AA[12,9:12]<- c( 0.08, 100.0, 50.00, 15.00)
## Block diagonal input.
Top <- matrix(nrow = 2, ncol = 4, data = AA[1:2 , 1:4] )
Bot <- matrix(nrow = 2, ncol = 4, data = AA[11:12, 9:12])
Blk1 <- matrix(nrow = 4, ncol = 8, data = AA[3:6 , 1:8] )
Blk2 <- matrix(nrow = 4, ncol = 8, data = AA[7:10 , 5:12])
AR <- array(dim = c(4, 8, 2), data = c(Blk1, Blk2))
overlap <- 4
# answer = (1, 1,....1)
Solve.block(Top, AR, Bot, B, overlap = 4)
# Now with 3 different B values
B3 <- cbind(B, 2*B, 3*B)
Solve.block(Top, AR, Bot, B3, overlap = 4)
```

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