is.ok: does a vector have the sum required to be a row or column of a
magic square?
Description
Returns TRUE
if and only if sum(vec)==magic.constant(n,d=d))
Usage
is.ok(vec, n=length(vec), d=2)
Arguments
- vec
Vector to be tested
- n
Order of square or hypercube. Default assumes order is equal
to length of vec
- d
Dimension of square or hypercube. Default of 2 corresponds to a square