mistat (version 0.999)

powerCircuitSimulation: The Power Circuit Simulator

Description

A simulator of a voltage conversion power circuit. The target output voltage of the power circuit is 220 volts DC. The circuit consists of 10 resistances labeled A to J, and 3 transistors, labeled K to M. These components can be purchased with different tolerance grades.

Usage

powerCircuitSimulation(rsA = 8200, rsB = 220000, rsC = 1000, 
                       rsD = 33000, rsE = 56000, rsF = 5600, 
                       rsG = 3300, rsH = 58.5, rsI = 1000, 
                       rsJ = 120, trK = 130, trL = 100, 
                       trM = 130, 
                       tlA = 5, tlB = 10, tlC = 10, 
                       tlD = 5, tlE = 5, tlF = 5, 
                       tlG = 10, tlH = 5, tlI = 5, 
                       tlJ = 5, tlK = 5, tlL = 10, 
                       tlM = 5, 
                       each = 50, seed = NA)

Arguments

rsA

the resistance ($\Omega$) of A. A single value or a vector of length n.

rsB

the resistance ($\Omega$) of B. A single value or a vector of length n.

rsC

the resistance ($\Omega$) of C. A single value or a vector of length n.

rsD

the resistance ($\Omega$) of D. A single value or a vector of length n.

rsE

the resistance ($\Omega$) of E. A single value or a vector of length n.

rsF

the resistance ($\Omega$) of F. A single value or a vector of length n.

rsG

the resistance ($\Omega$) of G. A single value or a vector of length n.

rsH

the resistance ($\Omega$) of H. A single value or a vector of length n.

rsI

the resistance ($\Omega$) of I. A single value or a vector of length n.

rsJ

the resistance ($\Omega$) of J. A single value or a vector of length n.

trK

the resistance ($\Omega$) of K. A single value or a vector of length n.

trL

the resistance ($\Omega$) of L. A single value or a vector of length n.

trM

the resistance ($\Omega$) of M. A single value or a vector of length n.

tlA

the tolerance of A. It is a number > 0 (e.g. 5% is 5.0)

tlB

the tolerance of B. It is a number > 0 (e.g. 5% is 5.0)

tlC

the tolerance of C. It is a number > 0 (e.g. 5% is 5.0)

tlD

the tolerance of D. It is a number > 0 (e.g. 5% is 5.0)

tlE

the tolerance of E. It is a number > 0 (e.g. 5% is 5.0)

tlF

the tolerance of F. It is a number > 0 (e.g. 5% is 5.0)

tlG

the tolerance of G. It is a number > 0 (e.g. 5% is 5.0)

tlH

the tolerance of H. It is a number > 0 (e.g. 5% is 5.0)

tlI

the tolerance of I. It is a number > 0 (e.g. 5% is 5.0)

tlJ

the tolerance of J. It is a number > 0 (e.g. 5% is 5.0)

tlK

the tolerance of K. It is a number > 0 (e.g. 5% is 5.0)

tlL

the tolerance of L. It is a number > 0 (e.g. 5% is 5.0)

tlM

the tolerance of M. It is a number > 0 (e.g. 5% is 5.0)

each

non-negative integer. Each element of previous parameters is repeated each times.

seed

a single value, interpreted as an integer. If specified make the simulation replicable.

Value

• A data frame, a matrix-like structure, with each * n rows and with columns: lll{ rsA numeric value of rsA rsB numeric value of rsB rsC numeric value of rsC rsD numeric value of rsD rsE numeric value of rsE rsF numeric value of rsF rsG numeric value of rsG rsH numeric value of rsH rsI numeric value of rsI rsJ numeric value of rsJ trK numeric value of trK trL numeric value of trL trM numeric value of trM tlA numeric value of tlA tlB numeric value of tlB tlC numeric value of tlC tlD numeric value of tlD tlE numeric value of tlE tlF numeric value of tlF tlG numeric value of tlG tlH numeric value of tlH tlI numeric value of tlI tlJ numeric value of tlJ tlK numeric value of tlK tlL numeric value of tlL tlM numeric value of tlM volts numeric output in volts ($V$) }

Details

Factors affect the voltage output $V$ via a chain of nonlinear equations: $$V = \frac{136.67(a+\frac{b}{Z(10)})+d(c+e)\frac{g}{f}-h}{1+d\frac{e}{f}+b[frac{1}{Z(10)+0.006(1+\frac{13.67}{Z(10)})]+0.08202a}}$$ where $$a = \frac{Z(2)}{Z(1)+Z(2)}$$ $$b=\frac{1}{Z(12)+Z(13)}(Z(3)+\frac{Z(1)Z(2)}{Z(1)+Z(2)})+Z(9)$$ $$c=Z(5)+Z(7)/2$$ $$d=Z(11)\frac{Z(1)Z(2)}{Z(1)+Z(2)}$$ $$e=Z(6)+Z(7)/2$$ $$f=(c+e)(1+Z(11))Z(8)+ce$$ $$g=0.6+Z(8)$$ $$h=1.2$$ with $Z(1),\ldots,Z(10)$ resistances in $\Omega$ of the 10 resistances and $Z(11),Z(12),Z(13)$ are the $h_{FE}$ values of three transistors.

References

Kenett, R., Zacks, S. with contributions by Amberti, D. Modern Industrial Statistics: with applications in R, MINITAB and JMP. Wiley.

See Also

pistonSimulation, simulationGroup

Examples

powerCircuitSimulation(seed=123, each=3)