mean
and standard deviation equal to sd
before truncation, and
truncated on the interval [lower, upper]
.dtnorm(x, mean=0, sd=1, lower=-Inf, upper=Inf, log = FALSE)
ptnorm(q, mean=0, sd=1, lower=-Inf, upper=Inf, lower.tail = TRUE, log.p = FALSE)
qtnorm(p, mean=0, sd=1, lower=-Inf, upper=Inf, lower.tail = TRUE, log.p = FALSE)
rtnorm(n, mean=0, sd=1, lower=-Inf, upper=Inf)
length(n) > 1
, the length is
taken to be the number required.dtnorm
gives the density, ptnorm
gives the distribution
function, qtnorm
gives the quantile function, and rtnorm
generates random deviates.$$f(x, \mu, \sigma) = \phi(x, \mu, \sigma) / (\Phi(u, \mu, \sigma) - \Phi(l, \mu, \sigma))$$ for $l <= 0="" x="" <="u$," and="" otherwise.="" p="">
$\mu$ is the mean of the original Normal distribution before
truncation,
$\sigma$ is the corresponding standard deviation,
$u$ is the upper truncation point,
$l$ is the lower truncation point,
$\phi(x)$ is the density of the corresponding normal
distribution, and
$\Phi(x)$ is the distribution function of the corresponding normal
distribution.
If mean
or sd
are not specified they assume the default values
of 0
and 1
, respectively.
If lower
or upper
are not specified they assume the default values
of -Inf
and Inf
, respectively, corresponding to no
lower or no upper truncation.
Therefore, for example, dtnorm(x)
, with no other arguments, is
simply equivalent to dnorm(x)
.
Only rtnorm
is used in the msm
package, to simulate
from hidden Markov models with truncated normal
distributions. These functions are merely provided for completion,
and are not optimized for numerical stability. To fit a hidden Markov
model with a truncated Normal response distribution, use a
hmmTNorm
constructor. See the hmm-dists
help page for further details.
dnorm
x <- seq(50, 90, by=1)
plot(x, dnorm(x, 70, 10), type="l", ylim=c(0,0.06)) ## standard Normal distribution
lines(x, dtnorm(x, 70, 10, 60, 80), type="l") ## truncated Normal distribution
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