# NOT RUN {
dbivCMP(lambda=10, nu=1, bivprob=c(0.4, 0.2, 0.3, 0.1), x=2, y=3, maxit = 100)
#this is equivalent to the pmf P(X=2,Y=3) of a bivariate Poisson
##with lambda1=3, lambda2=2, lambda3=1
# }
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