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Check whether two codons are synonymous.
# S3 method for CodonAlphabet areSynonymous(this, codons, ...)
A CodonAlphabet object.
A vector containing two codons.
Not used.
TRUE or FALSE.
For more information see CodonAlphabet.
CodonAlphabet
# NOT RUN { # create a CodonAlphabet object a<-CodonAlphabet() areSynonymous(a,c("TCC","TCT")) areSynonymous(a,c("TCC","CCT")) # }
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