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compareAssignments(problem, necessary = TRUE)n is a number of
alternatives. Cell [i, j] is TRUE if a_i is assigned to
class at least as good as class of a_j for all compatible value
functions.
perf <- matrix(c(5, 2, 1, 7, 0.5, 0.9, 0.4, 0.4), ncol = 2)
problem <- buildProblem(perf, 3, FALSE, c('g', 'g'), c(0, 0))
problem <- addAssignmentsLB(problem, c(1, 2), c(2, 3))
resultOfComparison <- compareAssignments(problem)
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