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Compute the other diagonal identity matrix. The result is basically a fast version of diag(n)[, n:1].
diag(n)[, n:1]
diagX(n)
positive integer.
a numeric \(n \times n\) matrix with many zeros -- apart from 1s in the other diagonal.
1
diag.
diag
# NOT RUN { diagX(4) for(m in 1:5) stopifnot(identical(diagX(m), diag(m)[, m:1, drop = FALSE])) # }
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