Daten der Form 8710230920 aufspalten in Jahr, Monat, Tag, Std, Min
u.datumdecode(d, YMDHMnames = c("Jahr", "Monat", "Tag", "Std", "Min"))
a numeric matrix (or vector) with 5 columns containing the year, month, etc.
numeric dates in the form YYMMDDHHMM.
(column) names to be used for the result.
?? (someone at SfS ETH)
R's proper date-time coding: DateTimeClasses
;
u.date
etc.
u.datumdecode(8710230920)
## Jahr Monat Tag Std Min
## 87 10 23 9 20
u.datumdecode(c(8710230900, 9710230920, 0210230920))
## Jahr Monat Tag Std Min
## [1,] 87 10 23 9 00
## [2,] 97 10 23 9 20
## [3,] 2 10 23 9 20
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