# NOT RUN {
# cat("Sequence.Name Haplotype.Name",
# "Population1 H1",
# "Population1 H2",
# "Population1 H3",
# "Population1 H2",
# "Population2 H4",
# "Population2 H5",
# "Population2 H6",
# "Population2 H4",
# "Population3 H7",
# "Population3 H7",
# "Population3 H7",
# "Population3 H7",
# file = "3_FindHaplo_Example2_modified.txt", sep = "\n")
#
# # Reading the alignment directly from file:
# HapPerPop(inputFile="3_FindHaplo_Example2_modified.txt",header=TRUE,
# saveFile=FALSE)
#
# cat("Sequence.Name Haplotype.Name",
# "Population1id1 H1",
# "Population1id2 H2",
# "Population1id3 H3",
# "Population1id4 H2",
# "Population2id1 H4",
# "Population2id2 H5",
# "Population2id3 H6",
# "Population2id4 H4",
# "Population3id1 H7",
# "Population3id2 H7",
# "Population3id3 H7",
# "Population3id4 H7",
# file = "4_FindHaplo_Example2_modified.txt", sep = "\n")
#
# # Reading the alignment directly from file. First column includes population
# # and individual names. Consequently, 12 populations are considered:
# HapPerPop(inputFile="4_FindHaplo_Example2_modified.txt",header=TRUE,
# saveFile=FALSE)
#
# # Population names within the input matrix first column goes from
# # character 1 to 11. Now 3 populations are considered:
# HapPerPop(inputFile="4_FindHaplo_Example2_modified.txt",header=TRUE,
# saveFile=FALSE,NameIniPopulations=1, NameEndPopulations=11)
#
# # If population names are set from character 1 to 3, all samples would
# # be treated as a single population
# HapPerPop(inputFile="4_FindHaplo_Example2_modified.txt",header=TRUE,
# saveFile=FALSE,NameIniPopulations=1, NameEndPopulations=3)
#
# # Reading the alignment directly from file, displaying only the
# # weighted matrix:
# HapPerPop(inputFile="4_FindHaplo_Example2_modified.txt",header=TRUE,
# saveFile=FALSE,NameIniPopulations=1, NameEndPopulations=11)[[1]]
#
# # Reading the alignment from an object and saving the two computed
# # distance matrices:
# FH<-read.table("3_FindHaplo_Example2_modified.txt",header=TRUE)
# HapPerPop(input=FH,header=TRUE,saveFile=FALSE)
#
# }
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