Convert an R object into a YAML string

Convert an R object into a YAML string

as.yaml(x, line.sep = c("", "", ""), indent = 2, omap = FALSE,
          column.major = TRUE, unicode = TRUE, precision = getOption('digits'))
x{ the object to be converted }
  line.sep{ the line separator character(s) to use }
  indent{ the number of spaces to use for indenting }
  omap{ determines whether or not to convert a list to a YAML omap; see Details }
  column.major{ determines how to convert a data.frame; see Details }
  unicode{ determines whether or not to allow unescaped unicode characters in output }
  precision{ number of significant digits to use when formatting numeric values }
If you set the omap option to TRUE, as.yaml will create ordered maps (or omaps) instead of normal maps.

The column.major option determines how a data frame is converted. If TRUE, the data frame is converted into a map of sequences where the name of each column is a key. If FALSE, the data frame is converted into a sequence of maps, where each element in the sequence is a row. You'll probably almost always want to leave this as TRUE (which is the default), because using yaml.load on the resulting string returns an object which is much more easily converted into a data frame via

Returns a YAML string which can be loaded using yaml.load or copied into a file for external use. YAML:

YAML omap type:

[object Object],[object Object] yaml.load as.yaml(1:10) as.yaml(list(foo=1:10, bar=c("test1", "test2"))) as.yaml(data.frame(a=1:10, b=letters[1:10], c=11:20)) as.yaml(list(a=1:2, b=3:4), omap=TRUE) as.yaml("multi") as.yaml(function(x) x + 1) as.yaml(list(foo=list(list(x = 1, y = 2), list(x = 3, y = 4)))) data manip
  • as.yaml
Documentation reproduced from package yaml, version 2.1.11, License: BSD_3_clause + file LICENSE

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