The expected value of the Zipf-PSS distribution only exists for \(\alpha\) values strictly
greater than 2. The value is obtained from the law of total expectation that says that: $$E[Y] = E[N]\, E[X],$$
where E[X] is the mean value of the Zipf distribution and E[N] is the expected value of a Poisson one.
From where one has that:
$$E[Y] = \lambda\, \frac{\zeta(\alpha - 1)}{\zeta(\alpha)}$$
Particularlly, if one is working with the zero-truncated version of the Zipf-PSS distribution.
This values is computed as:
$$E[Y^{ZT}] = \frac{\lambda\, \zeta(\alpha - 1)}{\zeta(\alpha)\, (1 - e^{-\lambda})}$$