mapLists: Replaces contents of list A with elements of list B...
Description
Replaces contents of list A with elements of list B
Usage
mapLists(A, B, removeNAs=TRUE)
Arguments
A
List, elements are coerced to character for mapping to B.
B
List.
removeNAs
Boolean, whether to remove the NAs that occur because an element was not found in B.
Value
Details
Combines two lists, A and B, such that names(A) are preserved, mapping to the
values of B, using names(B) as look up. Ie. replaces values in A with values
in B, using names(B) as look up for values in A.
Once more? See examples.
NB! None-mapped entries are returned as NA, but can be removed using removeNAs.