has.close
Check Whether Points Have Close Neighbours
For each point in a point pattern, determine whether the point has a close neighbour in the same pattern.
Usage
has.close(X, r, Y=NULL, …) # S3 method for default
has.close(X,r, Y=NULL, …, periodic=FALSE)
# S3 method for ppp
has.close(X,r, Y=NULL, …, periodic=FALSE, sorted=FALSE)
# S3 method for pp3
has.close(X,r, Y=NULL, …, periodic=FALSE, sorted=FALSE)
Arguments
- X,Y
Point patterns of class
"ppp"or"pp3"or"lpp".- r
Threshold distance: a number greater than zero.
- periodic
Logical value indicating whether to measure distances in the periodic sense, so that opposite sides of the (rectangular) window are treated as identical.
- sorted
Logical value, indicating whether the points of
X(andY, if given) are already sorted into increasing order of the \(x\) coordinates.- …
Other arguments are ignored.
Details
This is simply a faster version of (nndist(X) <= r)
or (nncross(X,Y,what="dist") <= r).
has.close(X,r) determines, for each point in the pattern X,
whether or not this point has a neighbour in the same pattern X
which lies at a distance less than or equal to r.
has.close(X,r,Y) determines, for each point in the pattern X,
whether or not this point has a neighbour in the other pattern
Y which lies at a distance less than or equal to r.
The function has.close is generic, with methods for
"ppp" and "pp3" and a default method.
Value
A logical vector, with one entry for each point of X.
See Also
Examples
# NOT RUN {
has.close(redwood, 0.05)
with(split(amacrine), has.close(on, 0.05, off))
# }